1. x - y
2. xy
3. y / x
4. x+y
5. y= x-6
6. 6x =y
7. y-x
8. x/y
9. x+y= 6
10. xy= 6
The sign of f on the interval -7/3 < x < -3/5 is always positive.
<h3>How to solve for the sign on the interval</h3>
We have the equation
(5x+3)(x−2)(3x+7)(x+5) > 0
Now when f(x) > 0
Then -7/3 < x < -3/5
This would tell us that the sign would become positive when it changes from the less than to greater than sign
<h3>Complete Question</h3>
f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2
What is the sign of f on the interval -7/3<x<-3/5?
answer choices
f is always positive on the interval
f is always negative on the interval
f is sometimes positive and sometimes negative on the interval
f is never positive or negative on the interval
Read more on polynomials here:
brainly.com/question/2833285
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these two bars | | mean <u>absolute value</u>
here's how to find x
| x - 7| = 2
first apply the absolute rule
x - 7 = 2 x - 7 = -2
in both equations add 7 on both sides
x - 7 + 7 = 2 + 7 x - 7 + 7 = -2 + 7
then simplify the expressions
x = 9 x = 5
now combine these two solutions to get your answer
x = 9 or x = 5
hopefully my explanation helps
