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3 years ago

What’s the largest fraction: 7/8, 5/8, 7/13, and 11/19

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Answer:

7/8

Step-by-step explanation:

7/8 = 0.875

5/8 = 0.625

7/13 = 0.538

11/19 = 0.579

So 7/8 is the largest

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Which side is adjacent to

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Answer:

Answer is on the pic

Step-by-step explanation:

I hope it's helpful!

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3 years ago

Here are the equations for 4

Kipish [7]

Answer:

Please see attached graph.

Step-by-step explanation:

The equations for straight lines are given as:

i) y = x +4

ii) y= x-4

Yon can form a table for values of x and y that are true for an equation and use these values as coordinates ( x,y ) to plot the graphs and view the lines to select the correct labels for the equations.

For i)

y= x+4

x y coordinates

-3 1 (-3,1 )

-2 2 (-2,2)

-1 3 (-1,3)

0 4 ( 0,4)

1 5 ( 1,5)

2 6 ( 2,6)

3 7 ( 3,7)

Plot the points on a graph tool and draw the line. Do the same for the second equation to view both graphs as shown in the attached graph.

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3 years ago

Nikolas calculated the volume of the prism. His work is shown below. A triangular prism. The triangular base has a base of 5.8 f

Brut [27]

Answer:

B he used the incorrect formula for the volume of the prism

3 0

3 years ago

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Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

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3 years ago

Televisions are on sale for 85% of the original price of $499. How do I find out the sale price.

natulia [17]

To find your sale price you must:
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just simply follow that operation and you're good to go

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4 years ago

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