An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u
ntil it has moved 6 m. What is the approximate final velocity of the block?
1 answer:
Answer:
5.02 m/s
Step-by-step explanation:
We are given that
Mass of block,m=8 kg
Initial velocity,u=3.2 m/s
Net force ,F=10 N
Distance,s=6 m
We have to find the approximate final velocity of the block.
We know that 
Using the formula

We know that

Using the formula


You might be interested in
Y - 6 = -3/7(x + 5)
y - 42/7 = -3/7x - 15/7
y = -3/7x + 27/7
X+1=y+1
X-Y= 0
Hope this helped you
Answer:
m∠x ≈ 32°
Step-by-step explanation:
We can see that we have to use tan∅ to solve this (opposite over adjacent)
tan(x) = 7/11
x = tan^-1 (7/11)
x = 32.4712
Answer:
The number is 48.
Step-by-step explanation:
x/8+3=9
x/8=9-3
x/8=6
x=6*8
x=48
Answer:
(-6,5)
Step-by-step explanation: