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Papessa [141]
2 years ago
13

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

ntil it has moved 6 m. What is the approximate final velocity of the block?
Mathematics
1 answer:
Softa [21]2 years ago
8 0

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that a=\frac{F}{m}

Using the formula

a=\frac{10}{8}=\frac{5}{4} m/s^2

We know that

v=\sqrt{u^2+2as}

Using the formula

v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}

v=5.02 m/s

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alexandr402 [8]
Six point eight four.

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5 0
3 years ago
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andreev551 [17]

Answer:

see explanation

Step-by-step explanation:

Part 1

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Part 2

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3 years ago
Given the fu8nction f(x) = 2(x + 10), find x if f(x) = 24.<br><br> A) 68<br> B) 7<br> C) 17<br> D) 2
lyudmila [28]
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3 years ago
Enter the slope-intercept equation for the image of line ℓ after a clockwise rotation of 90°. (Hint: To find the image of line ℓ
Free_Kalibri [48]

Answer:

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Step-by-step explanation:

From the graph attached,

If the line 'l' passes through two points A(0, -1) and B(4, 1).

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By this rule,

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B(4, 1) → B'(1, -4)

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y = -2x - 2

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of all the murder victims in 2010 whose relation to the offender was known, 24.8% were killed by a family member and 53% by an a
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