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Papessa [141]
2 years ago
13

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

ntil it has moved 6 m. What is the approximate final velocity of the block?
Mathematics
1 answer:
Softa [21]2 years ago
8 0

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that a=\frac{F}{m}

Using the formula

a=\frac{10}{8}=\frac{5}{4} m/s^2

We know that

v=\sqrt{u^2+2as}

Using the formula

v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}

v=5.02 m/s

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Answer:

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b) 18

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The Earl's height is unusual because the  z score does not lies in the given range of usual i.e -2 and 2

Step-by-step explanation:

Given:

Mean height, μ = 174 cm

Standard deviation = 6 cm

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a) The positive difference between Earl height and the mean = x - μ

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c) Now,

the z score is calculated as:

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or

z=\frac{192-174}{6}

or

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