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Sphinxa [80]
2 years ago
9

Factorise the following expression :​

Mathematics
2 answers:
eduard2 years ago
7 0

Answer:

ii)(x^2+5)(x+2)\\iv)(a^2-b)(a-b^2)

Step-by-step explanation:

ii)We\ are\ given,\\x^3+2x^2+5x+10\\Let's\ separate\ the\ terms\ the\ terms\ using\ the\ Associative\ Property\ Of\\ Addition:\\(x^3+2x^2)+(5x+10)\\=(x*x^2+2*x^2)+5*x+5*2\\=x^2(x+2)+5(x+2) [Taking\ out\ (x+2)\ from\ each\ term]\\=(x^2+5)(x+2) [Using\ the\ Distributive\ Property\ to\ re-combine\ the\ terms]

iv)We\ are\ given,\\a^3-a^2b^2-ab+b^3\\Lets\ again\ separate\ the\ terms\ using\ the\ Associative\ Property\ Of\\ Addition:\\(a^3-a^2b^2)+(-ab+b^3)\\=a^2(a-b^2)+(b(-a+b^2))\\Now,\\Here,\\We\ cannot\ directly\ apply\ Distributive\ Property\ as:\\a-b^2\neq -a+b^2\\Rather,\ just\ represent\ 1b\ in\ the\ second\ term\ as:\\-1*-1*b\\Hence,\\a^3-a^2b^2-ab+b^3\\=a^2(a-b^2)+(b(-a+b^2))\\=a^2(a-b^2)+(-1*b*-1(-a+b^2))\\=a^2(a-b^2)-b(a-b^2)\\=(a^2-b)(a-b^2)\ [Re-grouping\ the\ terms\ using\ Distributive\ Property]

Bas_tet [7]2 years ago
5 0

Answer:

x³+2x²+5x+10

x²(x+2)+5(x+2)

(x+2)(x²+5)

a³-a²b²-ab+b³

a²(a-b²)-b(a-b²)

(a-b²)(a²-b)

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The circumference of the outside of a ring is 66 mm, and it has an outer diameter of 21 mm. If the circumference of the inside o
scoray [572]

Answer:

Here Bub. (Nice PfP) I got aproximently 16 (15.924).

Step-by-step explanation:

The formula for Circumference if I remeeber right is pi times diameter. Now we can flip the equation to Circumference divided by pi. If pi is the standard pounding of 3.14, you will get 15.9235, almost 16

5 0
2 years ago
A pizzeria sells two types of pizza for lunch: pepperoni and cheese. The pepperoni pizza costs $8.50 and the cheese pizza costs
Usimov [2.4K]

Answer:

Let the no. Of cheese pizzas be x

Let the no. Of pepperoni pizzas be y

x + y = 45 (No. Of pizzas)

x = 45 - y

6x + 8.5y = 365 (cost of pizzas)

6(45-y) + 8.5y = 365

270 - 6y + 8.5y = 365

2.5y = 365 - 270

2.5y = 95

y = 95/2.5

y = 38

x = 7

Therefore 7 cheese pizzas were sold and 38 pepperoni pizzas were sold

Hope this helps!

7 0
2 years ago
a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the
alisha [4.7K]

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

                           = (150)²

                           = 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

                                                                            = 150 + (2×5)

                                                                            = 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

                                            = (160)²

                                            = 25600 m²

Area of road = Area of the park with road - Area of the park

                     = 25600 - 22500

                     = 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

                                                                              = 775000 rupees

6 0
2 years ago
I have a whole packet :(
Maslowich
12 A . my guess would be to divide 2175 by 18 which would give you 120.83
7 0
3 years ago
BRAINLEIST ANSWER TO WHOEVER GIVES ME CORRECT ANSWER FIRST
ivann1987 [24]
Great, because  y=2x+5 is 3xy kay.

4 0
3 years ago
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