The answer is 10. If you replace the number letters with the numbers you get 6 + 10 / 2 - 1. Then you follow PEMDAS, so first divide 10 with 2 to get five (6 + 5 - 1). Add 6 and 5 to get 11 and subtract 1 to get the final answer of 10.
Well, in order to know this answer you have to first multiply 10x10. After you have that answer you will multiply 1.653. The product of that will be your answer.
Answer:
The answers of all four questions are below.
Step-by-step explanation:
(5)4+2x=−2x+44
Step 1: Simplify both sides of the equation.
2x+4=−2x+44
Step 2: Add 2x to both sides.
2x+4+2x=−2x+44+2x
4x+4=44
Step 3: Subtract 4 from both sides.
4x+4−4=44−4
4x=40
Step 4: Divide both sides by 4.
4x/4=40/4
x=10
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(6)114−3x=194−11x
Step 1: Simplify both sides of the equation.
114−3x=194−11x
114+−3x=194+−11x
−3x+114=−11x+194
Step 2: Add 11x to both sides.
−3x+114+11x=−11x+194+11x
8x+114=194
Step 3: Subtract 114 from both sides.
8x+114−114=194−114
8x=80
Step 4: Divide both sides by 8.
8x/8 = 80/8
x=10
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(7)4x-12=-2x+36
4x-12+12=-2x+36+12
4x=-2x+48
4x+2x=-2x+48+2x
6x=48
6x/6=48/6
x=8
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(9)-3x+90=117-12x
-3x+90-90=117-12x-90
-3x=-12x+27
-3x+12x=-12x+27+12x
9x=27
9x/9=27/9
x=3
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Oh, and a tip if your having trouble with algebraic expressions I recommend you use mathpapa and symbolab when I was learning expressions this really helped me. Have a great day.
When adding these just add common numbers for instance those with the i variable and then the coefficients. We will get (-7+7i)
A.) If there are no restrictions, Number of committes possible = 9C5 = 126
b.) If both Jim and Mary must be in the committee, then we are now choosing 3 persons from the remaining 7 people. So the number of committes possible = 7C3 = 35
c.) If either Jim or Mary (but not both) must be on the committe, then there are 7 people availabe and 4 choices to make after taking either Jim or Mary. Also, there are 2 possible ways of choosing either Jim or May.
Theefore, Number of committe possible = 2(7C4) = 2(35) = 70
