Answer:
<u>The slope is -3.</u>
Step-by-step explanation:
The slope is the Rise/Run between the two points. The change in y for every change in x. Take the two points and calculate the:
RISE = (-6 - 3) = -9
RUN = (8 - 5) = 3
Rise/Run, or slope, is = -9/3 or -3
I graphed a line with slope of -3 and then added 18 to force the line to intersect the two given points.
Answer:
0.3164 = 31.64% probability the team wins all its conference games
Step-by-step explanation:
For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
A football team has a probability of .75 of winning when playing any of the other four teams in its conference.
The probability means that 
, and four games means that 
If the games are independent, what is the probability the team wins all its conference games?
This is P(X = 4). So
0.3164 = 31.64% probability the team wins all its conference games
Answer:
4/8
Step-by-step explanation:
Dividing a whole cantaloupe into eighths will give you 8/8 or 1. When it is cut in half then divided there is one half of 8/8 or there are 4/8 in one half. This is true because 1/2 and 4/8 are equal terms.
Hope this helps!
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
