So here just plug values into the quadratic formula x= -b+- sqr b^2-4ac / 2a
Answer:
The probability of getting two heads and a four is 1/24
Step-by-step explanation:
The probability of getting a head upon a single toss of a coin, assuming the coin is fair is 1/2.
The probability of getting two heads upon tossing two coins together will simply be the product of the individual probabilities;
P (HH) = 1/2 * 1/2 = 1/4
On the other hand, the probability of getting a four upon rolling a six sided number cube is;
1/6
This is because the number 4 occurs only once in a total possible of 6 numbers.
Therefore, the probability of getting two heads and a four;
P (HH4) = 1/2 * 1/2 * 1/6 = 1/24 since the three events are independent.
Look at the signs and turn it into an easier form:
35 - 13 + 8 + 6
= 36
Answer:
430.5
Step-by-step explanation:
1. We assume, that the number 525 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 525 is 100%, so we can write it down as 525=100%.
4. We know, that x is 82% of the output value, so we can write it down as x=82%.
5. Now we have two simple equations:
1) 525=100%
2) x=82%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
525/x=100%/82%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 82% of 525
525/x=100/82
(525/x)*x=(100/82)*x - we multiply both sides of the equation by x
525=1.219512195122*x - we divide both sides of the equation by (1.219512195122) to get x
525/1.219512195122=x
430.5=x
x=430.5
now we have:
82% of 525=430.5
