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chubhunter [2.5K]
3 years ago
6

Identify the angles that each have a measure of 124º.

Mathematics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

Angle 1, angle 3 and angle 7 will be the equal angles.

Step-by-step explanation:

In the figure attached,

Two lines are parallel and a transversal line is intersecting these parallel lines.

Congruent angles to the angle measuring 124° will be,

m(∠7) = 124° [Vertical angles]

m(∠1) = 124° [Corresponding angles]

m(∠3) = 124° [Alternate interior angles]

Therefore, ∠1, ∠7 and ∠3 will measure the same as 124°.

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tatuchka [14]
Convert 20% into a decimal like this >> 20/100 =0.2 now 0.2 x 60.00 =12 the answer hope it works.
7 0
3 years ago
A line has the equation -5x -14y +168 = 0
valkas [14]

Answer:

y = -5/14x + 12

Step-by-step explanation:

add 14y to both sides to isolate variables and divide everything by 14 to get 1y and boom

6 0
3 years ago
A company rents out 15 food booths and 23 game booths at the county fair. The fee for a food booth is $75 plus $9 per day. The f
Lapatulllka [165]

Answer:

M =  2620 + 16d

M = total money paid or earned

d = # of days

Step-by-step explanation:

15  food

23 game

Total Money  =  M = 15 * 75  + 9 d   +  23* 65  + 7d

M = 15 * 75  + 9 d   +  23* 65  + 7d

M  =  1125  + 1495 + 16d

M =  2620 + 16d

5 0
3 years ago
Item 14<br> Find the missing dimension. Use the scale factor 1 : 12.
Vitek1552 [10]

Answer:

3.84m

Step-by-step explanation:

If the scale for this Water tower is 1 : 12 then this means that for every 1cm of the model, the actual water tower has 12cm. Therefore, in order to find the actual depth of the water tower we first need to multiply the depth of the model by 12.

32cm * 12 = 384cm

1 cm is equal to 0.01 m , therefore we now have to multiply the depth of the actual water tower which is in cm by 0.01 to get the actual depth in meters

384 * 0.01 = 3.84m

7 0
2 years ago
For a quality control test, a company checks the miles per gallon (mpg) for a simple random sample of 100 minivans drawn from it
amm1812

Answer:

95% confidence interval for the average mpg of all minivans in the company's inventory is [15.22 mpg , 15.98 mpg].

Step-by-step explanation:

We are given that a company checks the miles per gallon (mpg) for a simple random sample of 100 minivans drawn from its current inventory.

The average mpg of these 100 minivans is 15.6 with a standard deviation of 1.9 mpg.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average mpg = 15.6 mpg

             s = sample standard deviation = 1.9 mpg

            n = sample of minivans = 100

            \mu = population average mpg

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.987 < t_9_9 < 1.987) = 0.95  {As the critical value of t at 99 degree

                                         of freedom are -1.987 & 1.987 with P = 2.5%}  

P(-1.987 < \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } } < 1.987) = 0.95

P( -1.987 \times {\frac{s}{\sqrt{n} } } < {\bar X -\mu} < 1.987 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.987 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.987 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.987 \times {\frac{s}{\sqrt{n} } } , \bar X+1.987 \times {\frac{s}{\sqrt{n} } } ]

                                      = [ 15.6-1.987 \times {\frac{1.9}{\sqrt{100} } } , 15.6+1.987 \times {\frac{1.9}{\sqrt{100} } } ]

                                      = [15.22 mpg , 15.98 mpg]

Therefore, 95% confidence interval for the average mpg of all minivans in the company's inventory is [15.22 mpg , 15.98 mpg].

It is appropriate to compute a confidence interval for this problem using the Normal curve as t test statistics is used when data should follow normal distribution.

7 0
3 years ago
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