Ask question

Ask question

All categories

emmainna [20.7K]

3 years ago

8

Find sin 0. 15 8 0 please help! very important

1 answer:

Nonamiya [84]3 years ago

3 0

Answer:

D

Step-by-step explanation:

In the phrase SOH - CAH - TOA, the SOH stands for "Sine = opposite / hypotenuse", hence, the answer would be 15 / 8.

You might be interested in

Solve x^2 + 6x = 24.

Sunny_sXe [5.5K]

Hello DestinyKiara99 o/
We can solve this equation using the quadratic formula
Check it out...

x² + 6x - 24 = 0

Δ = 6² - 4.1.(-24)
Δ = 36 + 96
Δ = 132

x = -6 +/- √132 x' = -3 + √33
<span> -------------- /
2 \
x'' = - 3 - </span>√33
The correct answer is the letter D
I hope this help =)

8 0

3 years ago

6. It takes Ms. Rogan 13.7 minutes to run 1 mile. How long does it take her to run 3.1 miles (a 5k!). *

Brums [2.3K]

Answer

42.47

Step-by-step explanation:

4 0

2 years ago

Which of these number sentences is not true

andrew-mc [135]

4,ooo,ooo mm equal 4km

6 0

3 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

What minus 31 equals to 213

faltersainse [42]

Answer:

244?

Step-by-step explanation:

7 0

3 years ago