Answer:
The range of weights of the middle 99.7% of M&M’s is between 0.8187 and 1.0203.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
Sample mean:
Sample standard deviation:
What is the range of weights of the middle 99.7% of M&M’s?
By the Empirical Rule, within 3 standard deviations of the mean, so:
0.9195 - 3*0.0336 = 0.8187.
0.9195 + 3*0.0336 = 1.0203.
The range of weights of the middle 99.7% of M&M’s is between 0.8187 and 1.0203.
Answer: 0.7
Step-by-step explanation:
7/10= 0.7
Answer:
Step-by-step explanations
Clay 1.5 0.12 30
Silty Clay 1.9 0.18 40
Clay Loam 2.4 0.25 40
Silty Clay Loam 2.4 0.25 50
Sandy Clay Loam 1.8 0.20 50
Sandy Clay 1.9 0.12 50
Silt 2.0 0.40 50
Silty Loam 2.4 0.43 50
Loam 2.0 0.54 50
Sandy Loam 1.4 0.75 50
Loamy Sand 0.8 0.88 50
Fine Sand 0.7 1.25 60
Answer:
Uhh, I guess 24? I don't understand this question