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SSSSS [86.1K]
3 years ago
10

Factor out 3^2 ^3−18^2 ^4

Mathematics
1 answer:
34kurt3 years ago
3 0
The factor of three is six factor of two is to 3 is three factor of two is 22 is four and poster of four is 22 Answer
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Identify the coefficients and constants in the expression. 2x – y + 5x
garri49 [273]
I believe the answer is 7x-y
7 0
2 years ago
Find the center and the radius for the circle, given the equation: X^2+16X+y^2-6y=-24
Alika [10]
The center of the circle is (5,3)
6 0
3 years ago
P=2a+b+c solve for c
Harman [31]
P = 2a + b + c

Subtract 2a + b on both sides

c = P - (2a+b)
c = P - 2a - b

Hope that helps :)
4 0
3 years ago
A retailer has determined that the cost C of
adelina 88 [10]
A. The expression given in the question is

c = 6x + (900000/x)
c = (6x^ +900000)/x
I hope that this is the expression that you were looking for.

b. When x = 240, then

c = [6 * (240)^2 + 900000]/ 240
   = (6 * 57600) + 900000/240
   = (345600 + 900000)/240
   = 5190

From the above deduction, it can be concluded that the cost of ordering and storing is 5190. I hope the procedure is clear enough for you to understand.
7 0
3 years ago
For what value of k, the zeroes of x2 + kx + 12 will differ by 1?
asambeis [7]

Let <em>a</em> and <em>b</em> be the zeroes of <em>x</em>² + <em>kx</em> + 12 such that |<em>a</em> - <em>b</em>| = 1.

By the factor theorem, we can write the quadratic in terms of its zeroes as

<em>x</em>² + <em>kx</em> + 12 = (<em>x</em> - <em>a</em>) (<em>x</em> - <em>b</em>)

Expand the right side and equate the coefficients:

<em>x</em>² + <em>kx</em> + 12 = <em>x</em>² - (<em>a</em> + <em>b</em>) <em>x</em> + <em>ab</em>

Then

<em>a</em> + <em>b</em> = -<em>k</em>

<em>ab</em> = 12

The condition that |<em>a</em> - <em>b</em>| = 1 has two cases, so without loss of generality assume <em>a</em> > <em>b</em>, so that |<em>a</em> - <em>b</em>| = <em>a</em> - <em>b</em>.

Then if <em>a</em> - <em>b</em> = 1, we get <em>b</em> = <em>a</em> - 1. Substitute this into the equations above and solve for <em>k</em> :

<em>a</em> + (<em>a</em> - 1) = -<em>k</em>   →   2<em>a</em> = 1 - <em>k</em>   →   <em>a</em> = (1 - <em>k</em>)/2

<em>a</em> (<em>a</em> - 1) = 12   →   (1 - <em>k</em>)/2 • ((1 - <em>k</em>)/2 - 1) = 12

→   (1 - <em>k</em>)²/4 - (1 - <em>k</em>)/2 = 12

→   (1 - <em>k</em>)² - 2 (1 - <em>k</em>) = 48

→   (1 - 2<em>k</em> + <em>k</em>²) - 2 (1 - <em>k</em>) = 48

→   <em>k</em>² - 1 = 48

→   <em>k</em>² = 49

→   <em>k</em> = ± √(49) = ±7

8 0
3 years ago
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