A. The expression given in the question is

c = 6x + (900000/x)
c = (6x^ +900000)/x
I hope that this is the expression that you were looking for.

b. When x = 240, then

c = [6 * (240)^2 + 900000]/ 240
= (6 * 57600) + 900000/240
= (345600 + 900000)/240
= 5190

From the above deduction, it can be concluded that the cost of ordering and storing is 5190. I hope the procedure is clear enough for you to understand.

7 0

3 years ago

For what value of k, the zeroes of x2 + kx + 12 will differ by 1?

asambeis [7]

Let a and b be the zeroes of x² + kx + 12 such that |a - b| = 1.

By the factor theorem, we can write the quadratic in terms of its zeroes as

x² + kx + 12 = (x - a) (x - b)

Expand the right side and equate the coefficients:

x² + kx + 12 = x² - (a + b) x + ab

Then

a + b = -k

ab = 12

The condition that |a - b| = 1 has two cases, so without loss of generality assume a > b, so that |a - b| = a - b.

Then if a - b = 1, we get b = a - 1. Substitute this into the equations above and solve for k :

a + (a - 1) = -k → 2a = 1 - k → a = (1 - k)/2

a (a - 1) = 12 → (1 - k)/2 • ((1 - k)/2 - 1) = 12

→ (1 - k)²/4 - (1 - k)/2 = 12

→ (1 - k)² - 2 (1 - k) = 48

→ (1 - 2k + k²) - 2 (1 - k) = 48

→ k² - 1 = 48

→ k² = 49

→ k = ± √(49) = ±7

8 0

3 years ago