Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
4 yards. The radius is half the diameter of the circle and the length of one point of the circle to the center of the circle.
Step-by-step explanation:
50x32=1600 then u divide it by 2 and get 800
Answer: <em>c</em>
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<em>Step-by-step explanation: Simple addition with decimals.</em>
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Answer:
Technically, yes. It's called epsilon, which is defined as an infinitely small number. So
2 + epsilon is the smallest number greater than 2. But for practical purposes no there isn't.
00
Step-by-step explanation:Not without limits. You can always move the .1 one place further from the interring. For example,
2.1>2.01
and
2.01>2.001
So, unless there are a limited number of decimal spaces, you can continually add an infinite amount of zeros behind the decimal point, followed by a one.
If you use two or three decimal spaces as a standard in your class, then the smallest decimal greater than 2 would be 2.01 or 2.001, respectively.
