Answer:
46,499 digits
Step-by-step explanation:
Total pages of book = 11,521
9 pages numbered 1 - 9 that need 1 digit each = 9 × 1
= 9 digits
90 pages numbered 10 - 99 that need 2 digits each = 90 × 2
= 180 digits
900 pages numbered 100 - 999 that need 3 digits each = 900 × 3
= 2,700 digits
9000 pages numbered 1000 - 9999 that need 4 digits each = 9000 × 4
= 36,000 digits
1522 pages numbered 1000 - 11521 that need 5 digits each = 1522 × 5
= 7,610 digits
Total digits needed = 9 digits + 180 digits + 2,700 digits + 36,000 digits + 7,610 digits
= 46,499 digits
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>
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5k^3-8-4k^2+5k^2-2+3k^3
Group like terms:
5k^3+3k^3-4k^2+5k^2-8-2
Add similar elements:
5k^3+3k^3+k^2-8-2
Add similar elements:
8k^3+k^2-8-2
Subtract the numbers:
8k^3+k^2-10
Your Answer Is 8k^3+k^2-10
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12/2 = 6, so;
7x-1 = 6
7x = 7
x = 1
Because both sides are equal, you do the same for 2x+4
2x+4 = 6
2x = 2
x = 1
