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Gwar [14]
3 years ago
5

(NEED HELP WITH NUMBER 1!!!)

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

35 ia the answer sorry if im wrong

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What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
padilas [110]

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

5 0
3 years ago
25m + 100 - 24m - 75 = 68.
Maksim231197 [3]

25m+100−24m−75=68

Step 1: Simplify both sides of the equation.

25m+100−24m−75=68

25m+100+−24m+−75=68

(25m+−24m)+(100+−75)=68(Combine Like Terms)

m+25=68

m+25=68

Step 2: Subtract 25 from both sides.

m+25−25=68−25

m=43

Answer:

m=43

8 0
3 years ago
Mee: 5324611502 Pa: here​
arlik [135]

Answer:

yuh

Step-by-step explanation:

3 0
2 years ago
If we have 2 bags containing marbles. bag a has 7 green and 6 black marbles. bag b has 8 yellow and 4 red marbles. if we pick ra
Elena L [17]
A.  (7/13)·(1/3)=7/39.       P=7/39
B.  (6/13)·(2/3)=12/39.    P=12/39
C.  (7/13)·(2/3)=14/39.    P=14/39
D.  (6/13)·(1/3)=6/39.      P=6/39

All the numbers from Bag B were written as thirds cause their probabilities could be simplified to make multiplying easier
8 0
3 years ago
The first one is it right or wrong?
gayaneshka [121]
The first one is wrong

(do you need help solving it?)
3 0
3 years ago
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