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serg [7]
3 years ago
12

the width of a rectangule is 4 feet and the diagonal length of the rectangle is 13 feet, which mesurment is closest to the lengt

h of this rectangle in feet
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
5 0

Answer:9 feet

Step-by-step explanation:

3241004551 [841]3 years ago
4 0

Answer:

52 feet

Step-by-step explanation:

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What is the value of (4 minus 2) cubed minus 3 times 4? Negative 20 Negative 4 4 20
Mamont248 [21]

Answer:

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Step-by-step explanation:

(4-2)^3 - 3*4

PEMDAS

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MD  multiply and divide from left to right

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10–{22–[(−9)+(−11)]} help i'M HAVING A bad day :( fix it
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-32

Step-by-step explanation:

10–{22–[(−9)+(−11)]}

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What is the unit cost per bottle if a pack of 6 bottles of juice sells for $4.80
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Step-by-step explanation:

7 0
2 years ago
A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p
Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, H_0 : p \leq 0.29  {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, H_1 : p > 0.29  {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

          T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = proportion of chips that do not fail in the first 1000 hours of their use = 32%

            n = sample of chips = 1500

So, <u>test statistics</u> = \frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }

                              = 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0
3 years ago
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