The first term of the arithmetic progression exists at 10 and the common difference is 2.
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How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
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A certificate of deposit earns 1% interest every three months. The interest is compounded.
What is the value of a $35,000 investment after 6 years?
$37,153.21
$39,438.88
$44,440.71
$56,295.30
A. 37,153.21
Answer:
Let A1=a1+a2+a3, A2=a2+a3+a4, and so on, A10=a10+a1+a2. Then A1+A2+⋯+A10=3(a1+a2+⋯+a10)=(3)(55)=165, so some Ai≥165/10=16.5, so some Ai≥17.
Step-by-step explanation:
Answer:
72°
Step-by-step explanation:
tan x= PN/OP=95/31
⇒x ≈ 72°
Make them both improper fractions
13/3 divided by 11/9
Divide = multiply reciprocal
13/3 * 9/11 = 117/11 = 10 7/11