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2 years ago

Can someone help me out please

Mathematics

2 answers:

Svetach [21]2 years ago

8 0

Answer:

area = (14 x 16) - (0.5 x 16 x 6) = 176 ft²

Step-by-step explanation:

zlopas [31]2 years ago

5 0

Answer:

A = 176 ft²

Step-by-step explanation:

2 shapes: one rectangle and 1 triangle:

Rectangle:

A = bh

A = 16(14)

A = 224

Triangle:

A = 1/2bh

A = 1/2(16)(6)

A = 48

Combined:

224 - 48

176

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Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

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Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

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Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

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