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3 years ago

5

In which Quadrant is the point (4, -2) located?

1 answer:

babymother [125]3 years ago

6 0

Answer:

Quadrant 4

Step-by-step explanation:

We go to the x-axis first and put a point on number 4, second we move that point along the y-axis till number -2

which is located in the 4th quadrant

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What is 2x3-4x5 and 3x6=

lukranit [14]

Answer:

4 I believe

Step-by-step explanation:

sorry if im wrong, (didn't know if the and was to add or multiply,sorry!)

3 0

3 years ago

Please help with this

snow_lady [41]

Answer:

B. $- \frac{9}{8}$

Step-by-step explanation:

$\huge\frac{ - 2 {a}^{ - 3} {b}^{2} }{a} \\ \\ \huge = \frac{ - 2 {b}^{2} }{a \times{a}^{ 3} } \\ \\ \huge = \frac{ - 2 {b}^{2} }{{a}^{ 4} } \\ \\ \huge = \frac{ - 2 \times {3}^{2} }{ {( - 2)}^{4} } \\ \\ \huge= \frac{ - 2 \times 9}{16} \\ \\ \huge \red{= - \frac{9}{8} }$

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3 years ago

Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1? f(x) = (x – 2i)(x – 3i) f(x) =

kykrilka [37]

Answer:

$P(x)=(x-2i)(x-3i)$

Step-by-step explanation:

Build a Polynomial Knowing its Roots

If we know a polynomial has roots x1, x2, ..., xn, then it can be expressed as:

$P(x)=a(x-x1)(x-x2)...(x-xn)$

Where a is the leading coefficient.

Note the roots appear with their signs changed in the polynomial.

If the polynomial has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1, then:

$P(x)=1(x-2i)(x-3i)$

$\mathbf{P(x)=(x-2i)(x-3i)}$

8 0

3 years ago

Read 2 more answers

4. What is y = (3x – 9)(x + 2) in standard

LenKa [72]

Answer:

B)y = 3x^2 - 3x-18

Step-by-step explanation:

y = (3x – 9)(x + 2)

y = 3x*x+3x*2-9*x-9*2

y = 3x^2 +6x-9x-18

y = 3x^2 - 3x-18

8 0

3 years ago

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Kevin can travel 22.50 miles in 0.3. What is his average speed in miles per hour?

weeeeeb [17]

His average speed will be 75 miles per hour. Hope it help!

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3 years ago