The theoretical yield of acetate is 2607 g. The actual yield of acetate is 1066.8 g. The percentage yield of acetate is 41%.
If 1 mole of vinegar contains 6.02 x 10^23 particles
x moles of vinegar contains 9.02 x 10^24 particles
x = 1 mole x 9.02 x 10^24 /6.02 x 10^23
x = 15 moles of vinegar
The reaction is as follows;
2HC2H3O2 + CaCO3 -----> Ca(C2H3O2)2 + H2O + CO2
Since 2 moles of vinegar reacts with 1 mole of carbonate
x moles of vinegar reacts with 16.5 moles of carbonate
x = 2 moles x 16.5 moles/ 1 mole
x = 33 moles of vinegar
We can see that the vinegar is the reactant in excess hence the carbonate is the limiting reactant.
Theoretical yield = 16.5 moles x 158 g/mol = 2607 g
Actual yield = 6.35 moles x 158 g/mol = 1066.8 g
Percent yield = 1066.8 g/2607 g × 100/1
= 41%
Learn more: brainly.com/question/13440572?
See Figure 4 below.
1. Draw a 7-carbon chain and number the carbon atoms (<em>Figure 1</em>).
2. Insert a triple bond between atoms 5 and 6 (<em>Figure 2</em>).
3. Attach a phenyl group to atom 3 (<em>Figure 3</em>).
4. Attach a Br to atom 1 (Figure 4).
And you have your structure.
<em>Note</em>: The C≡C triple bond takes <em>priority</em> in the naming, so we must number the chain from the other end. The correct name is
<em>7-bromo-5-phenylhept-2-yne </em>(all one word).
It means the process carried by the cell is spontaneous.
