Answer:
molar mass of nicotine will be 162.16g/mol
Explanation:
The mass of nicotine taken = 0.60g
The volume of solution = 12mL
the osmotic pressure of solution = 7.55 atm
Temperature in kelvin =298.15K (25+ 273.15)
The formula which relates osmotic pressure and concentration (moles per L) is:
π = MRT
Where
π = osmotic pressure (unit atm) = 7.55 atm
M = molarity (mol /L)
T= temperature = (K) = 298.15 K
R = gas constant = 0.0821 L atm /mol K
Putting values
Therefore
Molarity is moles of solute dissolve per litre of solution
The volume of solution in litre = 0.012 L
we know that
molar mass =
Percent yield is 23.11 % when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2.
Explanation:
Balanced equation for the chemical reaction:
2C8H18 + 25O2 → 16CO2 + 18H2O
data given:
CO2 formed (actual yield) = 162.8 grams
mass of oxygen = 218 grams
16 moles of CO2 formed when 5 moles of oxygen reacted
3.6 moles of CO2 formed when 6.8 moles of oxygen reacted.
In the reaction 16 moles of CO2 will have 44.01 x 16
theoretical yield of CO2 = 704.16 grams
percent yield = x100
putting the values in the above equation
percent yield = x 100
= 0.23 x 100
= 23.11 %
Percent yield is 23.11 %.
Answer: Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.
Explanation: I hope that helped!
Answer: The rate will increase by a factor of 9.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
Given: Order with respect to = 2
Order with respect to = 1
Thus rate law is:
k= rate constant
It is given that the initial concentration of NO is tripled while all other factors stayed the same
Thus the rate will increase by a factor of 9.