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AlladinOne [14]
3 years ago
8

Draw the structural formula for 1 bromo 3 phenyl 5 heptyne

Chemistry
1 answer:
MrRissso [65]3 years ago
6 0

See Figure 4 below.

1. Draw a 7-carbon chain and number the carbon atoms (<em>Figure 1</em>).

2. Insert a triple bond between atoms 5 and 6 (<em>Figure 2</em>).

3. Attach a phenyl group to atom 3 (<em>Figure 3</em>).

4. Attach a Br to atom 1 (Figure 4).

And you have your structure.

<em>Note</em>: The C≡C triple bond takes <em>priority</em> in the naming, so we must number the chain from the other end. The correct name is

<em>7-bromo-5-phenylhept-2-yne </em>(all one word).

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Hello,

In this case, we write the reaction again:

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But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:

m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2

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