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Monica [59]
3 years ago
11

The bacteria in a petri dish culture are self duplicat

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

Yes, the bacteria in the Petri dish culture *are* duplicating.

Step-by-step explanation:

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In the Pi Corporation, 4/5 of the managers are female. If there are 64 female managers, how many managers in total are there? Ho
oksano4ka [1.4K]

Step-by-step explanation:

\frac{4}{5}  = 64 \\  \frac{1}{5}  = 64 \div 4 \\ \:  \:  \:  \:  \:  \:   = 16 \\ total \: managers \:  = 16 \times 5 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 80 \\ number \: of \: male \:  \: managers \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{5}{5}  -  \frac{4}{5}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{1}{5}  = 16

<em>hop</em><em>e</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

5 0
3 years ago
The formula a = 118e0.024t models the population of a particular city, in thousands, t years after 1998. when will the populatio
andriy [413]
Given that the population has been modeled by the formula:
a=118e^(0.024t), the time taken for the population to hit 140k will be given by:
140000=118e^(0.024t)
solving for t we shall have:
140000/118=e^(0.024t)
thus;
0.024t=ln(140000/118)
t=1/0.024*ln(140000/118)
t=295
thus the time the population will be 140000 will be:
1998+295
=2293
6 0
3 years ago
LABEL THE TRIANGLE!! PLEASE HELP!!
Anettt [7]

Answer:

Determination of HYP,OPP,ADJ with respect to x.

<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>

<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>

<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>

8 0
3 years ago
Please help!!!! My assignment is almost due!!!
NeX [460]

Answer:

15

Step-by-step explanation:

the triangles are similar so will be the same proprotion,

I have attached a picture showing how I solved this. the second traingle is 3 times as large (15 by 12)   compared to the first triangle which is 4 by 5.

3 0
3 years ago
Read 2 more answers
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
4 years ago
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