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OLga [1]
3 years ago
8

The area of a square is 9 sq. cm. One side length is 3 cm. What is the other side length?

Mathematics
2 answers:
madam [21]3 years ago
6 0
The side length 9sps behave. S s. Shahebgshehzgbzbh eugenics
mamaluj [8]3 years ago
6 0

Answer: 3

Step-by-step explanation: 3x3 is 9, and one side is 3 and we have square centimeters so 3 squared  or 3x3 is 9 which makes my answer correct, sorry if it was bad explanation this was the easiest question ive answered, plz follow me at twitch, at InfernoEliteGamingYT21

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Explain the connection between factors of a polynomial, zeros of a polynomial function, and solutions of a polynomial equation.
MrRissso [65]

Answer:

Step-by-step explanation:

Solutions, zeros, and roots of a polynomial are all the same exact thing and can be used interchangeably.  When you factor a polynomial, you solve for x which are the solutions of the polynomial.  Since, when you factor a polynomial, you do so by setting the polynomial equal to 0, by definition of x-intercept, you are finding the zeros (don't forget that x-intercepts exist where y is equal to 0). There's the correlation between zeros and solutions.  

Since factoring and distributing "undo" each other (or are opposites), if you factor to find the zeros, you can distribute them back out to get back to the polynomial you started with.  Each zero or solution is the x value when y = 0.  For example, if a solution to a polynomial is x = 3, since that is a zero of the polynomial, we can set that statement equal to 0: x - 3 = 0.  What we have then is a binomial factor of the polynomial in the form (x - 3).  These binomial factors found from the solutions/zeros of the polynomial FOIL out to give you back the polynomial equation.

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3 years ago
Please help me with this question, image attached.
hichkok12 [17]

Answer:

corresponding angles

Step-by-step explanation:

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4 0
3 years ago
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Create a word problem that involves speed
lana66690 [7]

A hockey puck is sliding on frictionless ice on an infinite hockey rink.
Its speed is 36 km/hour.  How far does the puck slide in 10 seconds ? 

 (36 km/hr) x (1,000 m/km) x (1 hr/3600 sec) x (10sec) =

         (36 x 1,000 x 10 / 3,600) meters  =  <em>100 meters</em>

What is the puck's speed in miles per hour ?

        (36 km/hr) x (0.6214 mi/km)  =  <em>22.37 mi/hr</em>


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3 years ago
What is the difference between the profits Mr.Brown's store earned in the first quarter and the third quarter?
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The answer is A, because $9,841.28 minus $7,429.84 is <span>$2,411.44</span>
8 0
3 years ago
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Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

 ( \frac{x^{2}-2xy+y^{2}}{2})-(\frac{x^{2}+2xy+y^{2}}{2})-16=0

* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
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