Answer:
The 80% confidence interval is 
Step-by-step explanation:
From the question we are told that
The sample size is n = 23
The sample mean is 
The standard deviation is 
From the question we are told the confidence level is 80% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of 
is
Generally the margin of error is mathematically represented as
=> 
Generally 80% confidence interval is mathematically represented as
=>
Two hundred eighty nine million four hundred fifty two thousand one hundred two and 52 hundredths
Answer:
9w-15x+3
Step-by-step explanation:
3(3W – 5x + 1); using distributive property
3 times 3w= 9w
3 times -5x= -15x
3 times 1=3
combine; 9w-15x+3
Answer:
For 99% of confidence interval is 67.5±1.3524
Step-by-step explanation:
Given:
Mean height =67.5 inches
Standard deviation:2.1 inches
Z at 99%.
No of samples 16.
To find:
confidence interval
Solution:
We have formula for confidence interval,
=mean ±Z*{standard deviation/sqrt(no.of observation)}
Now
Z=99%
has standard value as ,
Z=2.576
Confidence interval= mean±Z{standard deviation/sqrt(No. of samples)}
=67.5±2.57{(2.1/sqrt(16)}
=67.5±2.576(2.1/4)
=67.5±1.3524
Answer:
Step-by-step explanation:
Given
Required
The nth term
The given sequence is a geometric sequence.
So, first we identify the first term
Calculate common ration
or 
So, the nth term is:
