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Shalnov [3]
3 years ago
10

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

hem?
A.
As the distance increases by a factor, the electric force increases by the square of that factor.
B.
As the distance increases by a factor, the electric force increases by twice that factor.
C.
As the distance increases by a factor, the electric force decreases by twice that factor.
D.
As the distance increases by a factor, the electric force decreases by the same factor.
E.
As the distance increases by a factor, the electric force decreases by the square of that factor.
Physics
1 answer:
const2013 [10]3 years ago
4 0

The electric force between two point charges is given by:

F = (1/(4πε₀))Qq/r²

F is the electric force, Q and q are the two charges, and r is the distance between the charges.

F is proportional to the inverse square of r. That means if you increase r by a factor k, then F will decrease by a factor k².

Choice E.

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A stone of mass m is thrown upwards at an angle φ. The moment the stone leaves your hand it has an acceleration (friction is neg
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The correct answer is:

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Explanation:

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3 years ago
Technician A says that the aspect ratio of a tire represents the relationship between the tire's cross-sectional height to its c
earnstyle [38]

Answer:

Technician A

Explanation:

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6 0
4 years ago
Calculate the gravitational potential energy of a body of mass 40 kg at a vertical height of 10 m. ( g = 9.8 m/s2)
olganol [36]
Ep= mgh
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8 0
4 years ago
A 0.17kg ball rolls at 0.75m/s to the right on a frictionless surface and collides with a 0.17kg ball rolling to the left at 0.6
mario62 [17]

Both momentum and kinetic energy are conserved in elastic collisions (assuming that this collision is perfectly elastic, meaning no net loss in kinetic energy)

To find the final velocity of the second ball you have to use the conversation of momentum:

*i is initial and f is final*

Δpi = Δpf

So the mass and velocity of each of the balls before and after the collision must be equal so

Let one ball be ball 1 and the other be ball 2

m₁ = 0.17kg

v₁i = 0.75 m/s

m₂ = 0.17kg

v₂i = 0.65 m/s

v₂f = 0.5

m₁v₁i + m₂v₂i = m₁v₁f + m₂v₂f

Since the mass of the balls are the same we can factor it out and get rid of the numbers below it so....

m(v₁i + v₂i) = m(v₁f + v₂f)

The masses now cancel because we factored them out on both sides so if we divide mass over to another side the value will cancel out so....

v₁i + v₂i = v₁f + v₂f

Now we want the final velocity of the second ball so we need v₂f

so...

(v₁i + v₂i) - v₁f = v₂f

Plug in the numbers now:

(0.75 + 0.65) - 0.5 = v₂f

v₂f = 0.9 m/s


8 0
3 years ago
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