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We need to considerate only the horizontal component of the motion of the toy car.
The formula for the distance in a decelerated motion is:
s = s₀ + v₀·t - 1/2·a·t²
where:
s₀ = initial position = 0
v₀ = initial velocity = 1.21 m/s
t = time elapsed = 0.342 s
a = deceleration = 0.131 m/s²
Plugging in numbers:
s = 0 + 1.21×0.342 - 0.5×0.141×(0.342)²
= 0.406 m
Hence, the toy car traveled a distance of about 41 cm.
Answer:
Zero work done,since the body isn't acting against or by gravity.
Explanation:
Gravitational force is usually considered as work done against gravity (-ve) and work by gravity ( +ve ) and also When work isn't done by or against gravity work done in this case is zero.
Gravitational force can be define as that force that attracts a body to any other phyical body or system that have mass.
The planet been considered as our system in this case is assumed to have mass, and ought to demonstrate such properties associated with gravitational force in such system. Such properties include the return of every object been thrown up as a result of gravity acting downwards. The orbiting nature of object along an elliptical part when gravitational force isn't acting on the body and it is assumed to be zero.
