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gtnhenbr [62]
3 years ago
6

A.) For this linear function, what happens to the function’s values after many iterations?

Mathematics
1 answer:
velikii [3]3 years ago
5 0
It can be helpful to use technology (a spreadsheet program or graphing calculator) to help you with iterated functions. What you are doing is evaluating the function using its output as new input.

(A) Whenever the magnitude of the slope of a function is less than 1, it will iterate toward the point where it intersects the line y = x. Here the magnitude o the slope is 1/2, so the final value in this case will approach
.. x = y = (-1/2)x +3
.. 3/2x = 3 . . . . . . . . add x/2
.. x = 2 . . . . . . . . . . . multiply by 2/3

You can see several iterations in the table in the figure here.


(B) The values get closer to 2 in each case.

_____
Iteration of this function is like drawing a spiral on the graph. Start with some point on the function curve, such as (0, 3). Draw a horizontal line to the line y=x. this gives you x=3. Now draw a vertical line to the function curve. This will give you the point (3, f(3)) = (3, 1.5). Draw a horizontal line to y = x, repeating as many times as you like. You will see the points get closer and closer to (2, 2) with each loop around the spiral.

If the slope of the function is greater than 1, the "spiral" will diverge instead of converging.

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Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14
PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_{0}e^{-\lambda t}

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_{0}e^{-0.00012097\cdot t}

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_{0}e^{-0.00012097\cdot t}

Simplifying:

0.10=e^{-0.00012097\cdot t}

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=\frac{log 0.10}{-0.00012097}

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0
3 years ago
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Answer:

3:5=_____%

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Oliga [24]

Answer:

x = 8 units

Step-by-step explanation:

Note that the ratio of the middle-length legs is 12/18, and that of the shortest-length legs is x/12.

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