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jeka57 [31]
3 years ago
8

Create an explicit formula of the sequence. 7, 14, 28, 56, .... Find the 10th term of the sequence. Complete your work in

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

3584

Step-by-step explanation:

These are the terms of a geometric sequence with n th term

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

r = 14 ÷ 7 = 28 ÷ 14 = 56 ÷ 28 = 2 and a = 7, thus

a_{10} = 7(2)^{9} = 7 × 512 = 3584

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Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou
Anna35 [415]
For this case we have the following equation:
 3 \sqrt{x+6}=-12
 Rewriting we have:
 \sqrt{x+6}= \frac{-12}{3}
 \sqrt{x+6}=-4
 We raise both members of the equation to the square:
 (\sqrt{x+6})^2=(-4)^2
 Rewriting we have:
 x+6=16
 x=16-6
 x=10
 It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
 3 \sqrt{10+6}=-12
 3 \sqrt{16}=-12
 3(4)=-12
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 Answer:
 
The solution is:
 
x=10
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6 0
3 years ago
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natulia [17]

Answer:

=  -  {m}^{2}  - 3n + 13

Step-by-step explanation:

- (m \times m + 3n - 13)

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- ( {m}^{2}  + 3n - 13)

=  -  {m}^{2}  - 3n + 13

7 0
3 years ago
The surface area S , of a right rectangular prism with length l , width w ,and height h can be found using the formula below
Yakvenalex [24]
First, replace all variables with the given values.
12(9) + 9(2) + 2(12) 
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3 years ago
Simplify without the absolute value |x+3| ; if x&gt;2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

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|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

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x+3\ge 0

Subtract 3 on both sides

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*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

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x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
Mr. Phan fills a portion of his pool with water on Monday. Then on Tuesday, he fills the pool with water coming from a hose at a
Roman55 [17]

Answer: .6 ft. every hour

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3 years ago
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