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3 years ago

69 minutes equals how many hours and minutes?

Mathematics

1 answer:

Anestetic [448]3 years ago

7 0

Answer:

1 hour and 9 minutes

Step-by-step explanation:

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HELP PLEASE!! WILL MARK BRAINLIEST!!!!

elixir [45]

Answer:

see below

Step-by-step explanation:

$\frac{1}{x^{2} } + \frac{2}{y}/ \frac{5}{x} -\frac{6}{y^2}$

find common denominator and add the fractions in numerator and denominator:

1/x² + 2/y = y+2x²/x²y

5/x -6/y² =5y² -6x/xy²

(y+2x²)/x²y / (5y²-6x)/xy² change into multiplication

(y+2x²)/x²y * xy²/(5y²-6x)

$\frac{y+2x^{2} }{x^{2} y} *\frac{xy^{2} }{5y^{2}-6x }$ simplify

y(y+2x²)/ x(5y²-6x)

4 0

3 years ago

The edge length of a cube is 17 cm. Identify the length of its diagonal. Round to the nearest tenth, if necessary. HELP PLEASE!!

lara31 [8.8K]

Answer:

29.4 cm

Step-by-step explanation:

The length of the space diagonal can be found to be the root of the squares of the three orthogonal edge lengths. For a cube, those edge lengths are all the same, so the diagonal length is ...

d = √(17^2 + 17^2 +17^2) = 17√3 ≈ 29.4 . . . . cm

_____

Consider a rectangular prism with edge lengths a, b, c. Then the face diagonal of the face perpendicular to edge "a" has length ...

(face diagonal)^2 = (b^2 +c^2)

and the space diagonal has length ...

(space diagonal)^2 = a^2 + (face diagonal)^2 = a^2 +b^2 +c^2

So, the length of the space diagonal is ...

space diagonal = √(a^2 +b^2 +c^2)

when the prism is a cube, these are all the same (a=b=c). This is the formula we used above.

3 0

3 years ago

The radioisotope Mo-91 has a t1/2 of 15.5min. A sample decays at the rate of 954counts/min (954cpm). After how many minutes will

TiliK225 [7]

Step-by-step explanation:

Transcribed image text: Spectra Analysis 7 100 80 60 40 20 150 50 STRUCTURE 60 40 20 0 180 160 140 120 100 8O

5 0

3 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago

Write an algebraic expression for 84 more than the product of 167 and b

Ket [755]

Answer:

167b + 84

Step-by-step explanation:

Multiplication is indicated between a number and a variable by writing them next to each other. A "product" is the result of multiplication, so "the product of 167 and b" is written 167b.

If you want a value that is 84 more than that, you get it by adding 84.

167b + 84

4 0

3 years ago