2 years ago

Can somebody help me? Thank you!

Mathematics

1 answer:

xeze [42]2 years ago

6 0

Answer:

Sorry dear this is too hard

Step-by-step explanation:

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Help (20 points, due tmr!! ) *pic below* :)

sveta [45]

Angles:
2 acute angles and 2 obtuse angles

Sides:
2 pairs pf parallel sides

7 0

3 years ago

Y=-3+6and y=1/3x-8 determine if the equation are parallel, perpendicular or neither

Gelneren [198K]

Slope intercept form: y = mx + b

m = slope and b = y-intercept

The equation is: y = -3x + 6

The m value for this is -3, so the line has a slope of -3. If y = 1/3x - 8 was parallel to y = -3x + 6 then they would have the same slope, which they do not. So they aren't parallel.

The find the slope of a perpendicular line, take the negative reciprocal of the slope of y = -3x + 6. The negative reciprocal of -3 is 1/3. y = 1/3x - 8 has a slope of 1/3, so they are perpendicular to each other.

7 0

2 years ago

3n² + 2n - 8=0 Solve each equation with the quadratic formula

8_murik_8 [283]

Answer:

-2,4/3

Step-by-step explanation:

ax²+bx+c=0

$x=\frac{-b \pm\sqrt{b^2-4ac} }{2a} \\3n^2+2n-8=0\\n=\frac{-2\pm\sqrt{2^2-4*3*(-8)} }{2*3} \\n=\frac{-2 \pm \sqrt{4+96}}{6} }\\n=\frac{-2 \pm 10}{6} \\n=\frac{8}{6} =\frac{4}{3}\\or~n=\frac{-12}{6}=-2$