Can somebody help me? Thank you!

You have an ice cream scoop with a 2-inch diameter. You have an ice cream cone with a 2-inch diameter and a height of 5 inches.

IRISSAK [1]

Answer:

Since the volume of the cone is bigger than the volume of the scoop, it won't spill.

Step-by-step explanation:

In order to calculate if the ice cream will spill we will need to calculate the volume on the ice cream scoop and the volume of the cone. If the volume of the scoop is bigger than the cone it will spill.

volume scoop = (4/3)*pi*r³ = (4/3)*pi*(2/2)³ = 4.1888 in³

volume cone = (pi*r²*h)/3 = [pi*(2/2)²*5]/3 = 5.236 in³

Since the volume of the cone is bigger than the volume of the scoop, it won't spill.

4 0

3 years ago

Please help ASAP with this question

jeka57 [31]

Answer:

B. 7.9 in^2

Step-by-step explanation:

Part I.

Finding the fraction of the circle that is the sector

To start, let’s find the fraction of the circle that the sector covers. Since the measure of the central angle is 36, we get 36/360 or 1/10 of the circle.

Part II.

Finding the area of the Circle

The area of a circle is pi*r^2. Since r=5, then the area is 25pi.

Part III.

Finding the area of the sector.

Since the sector is 1/10 of the circle, its area is 1/10 of the circle’s area. So the area of the sector is 25/10*pi or (5/2)pi. This is approximately 7.9 in^2.

6 0

3 years ago

Pls solve this questions 4and 5

Viktor [21]

Answer:

86km/h

80km/h

Step-by-step explanation:

weighted average

bus took 5hrs so van took 3.75 hrs

300/3.75

6 0

2 years ago

Need help please!! Will give points

Nataly [62]

Answer:

1. $\bar X=5.10$

2. $\sigma=0.47$

3. $\sigma^2=0.22$

Step-by-step explanation:

QUESTION 1

The given data set for the expenditure is

$4.85,5.10,5.50,4.75,4.50,5.00,6.00$

The formula for calculating the mean is given by,

$\bar X=\frac{\sum x}{n}$

We need to add all the expenditure and divide by the total number of days.

$\bar X=\frac{4.85+5.10+5.50+4.75+4.50+5.00+6.00}{7}$

This gives us,

$\bar X=\frac{35.7}{7}$

$\Rightarrow \bar X=5.10$ to the nearest hundredth.

QUESTION 2

The standard deviation of the data set is given by the formula;

$\sigma =\sqrt{\frac{\sum(x-\bar X)^2}{n} }$

This implies that,

$\sigma =\sqrt{\frac{(4.85-5.10)^2+(5.10-5.10)^2+(5.50-5.10)^2+(4.75-5.10)^2+(4.50-5.10)^2+(5.00-5.10)^2+(6.00-5.10)^2}{7} }$

This will give us,

$\sigma =\sqrt{\frac{(-0.25)^2+(0.00)^2+(0.40)^2+(-0.35)^2+(-0.60)^2+(-0.10)^2+(0.90)^2}{7} }$

$\sigma =\sqrt{\frac{0.0625+0+0.16+0.1225+0.36+0.01+0.81}{7} }$

$\sigma =\sqrt{\frac{61}{280} }$

$\sigma =0.466775$

to the nearest hundredth,

$\sigma =0.47$ .

QUESTION 3

The variance is the square of the standard deviation.

$\sigma^2 =(0.46675)^2$

$\sigma^2 =0.217857$

To the nearest hundred gives,

$\sigma^2 =0.22$

3 0

3 years ago

The roof of a grain silo is in the shape of a cone. The inside radius is 20 feet, and the roof is 10 feet tall. Below the cone i

nirvana33 [79]

Answer:

41887.90 cubic feet

Step-by-step explanation:

We need to find the volume of the silo.

We simply need to find the volume of the cylindrical part and the conical part and add them together.

The body of the silo is a cylinder with height of 30 ft and radius of 20 ft and the roof is a cone with height 10 ft and radius 20 ft.

The volume of a cylinder is given as:

$V = \pi r^2h$

The volume of a cone is given as:

$V = \frac{1}{3} \pi r^2H$

where r = radius of cylinder and cone

h = height of cylinder

H = height of cone

Adding them together, we have that the volume of the silo is:

$V = \pi r^2h + \frac{1}{3} \pi r^2H$

$V = \pi r^2 (h + \frac{1}{3}H)\\ \\V = \pi * 20^2 (30 + [\frac{1}{3}* 10]) \\\\V = 1256.64 ( 30 + 3.33)\\\\V = 1256.64(33.33)\\\\V = 41887.90 ft^3$

The volume of the silo is 41887.90 cubic feet.

5 0

2 years ago