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vlabodo [156]
3 years ago
12

Please solve this problem

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

<h2>176 cm²</h2>

Step-by-step explanation:

you have a square and 4 equal triangles, you find the area of all, and you sum.

square area = l²

8² = 64 cm²

triangle area = b*h/2

8 * 7 : 2 = 28 cm²

now we sum 1 square's area and 4 triangles' area.

64 + 28 + 28 + 28 + 28 = 176 cm²

or

64 + (28 * 4) = 176 cm²


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pashok25 [27]

Answer:

Abbrah is the best shooter.

Step-by-step explanation:

Hannah made 0.7 which is equal to 70 out of 100 shots.

Dinah made 3/4 which is equal to 75 out of 100 shots.

Abbrah made 9/10 shots which is equal to 90 out of 100 shots.

8 0
3 years ago
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Explain how you can use reasoning to compare two fractions with the same denominator
Talja [164]
When two fractions have the same denominator, you can compare which fraction is greater by just comparing the numerators.
For example, if you have 2/5 and 3/5, the denominators are the same. So you can just look at the numerators. 3 is greater than 5, so 3/5 is greater than 2/5.

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7 0
4 years ago
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
HELP!! I will award brainliest!!!
Ugo [173]

Answer: c

Step-by-step explanation:

5 0
3 years ago
ABCD has a perimeter of 27 units and is dilated by a scale factor of 1/3. What is the perimeter of A¹B¹C¹D¹?
Alex17521 [72]

Answer:

Perimeter of A'B'C'D' = 9 units

Step-by-step explanation:

Given:

Perimeter of ABCD = 27 units

Scale factor = 1 / 3

Find:

Perimeter of A'B'C'D'

Computation:

Perimeter of A'B'C'D' = 1/3[Perimeter of ABCD]

Perimeter of A'B'C'D' = 1/3[27]

Perimeter of A'B'C'D' = 9 units

4 0
4 years ago
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