Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
Answer:
56/8 = 7 pieces of paper
Step-by-step explanation:
- The sample size is 64.
- The point estimate of the population proportion is 0.625.
-The margin of error is approximately 16%.
- 67
substitute the given values for x and y into the expression and evaluate
= - 6(2)³ - (4)² - 3 = ( - 6 × 8 ) - 16 - 3 = - 48 - 16 - 3 = - 67
42 if the base is 6 and the 7 is height, while if the base is 7 and the 2 is height the answer is 12 , then , if the 2 is base and then the 6 is height the answer is 12 again
Step-by-step explanation:
thats all