Step-by-step explanation:
Rate of drop of temperature = Change in temperature/Rate
=> (165 - 135)/15
=> 30/15
=> 2 ⁰F/min
Now, The time at which the temperature of will be 70⁰F = 70/Rate
=> 70/2
=> 35 min
Time for 110⁰ F
=> 110/2
=> 55 min
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3/20 as a decimal equivalent is <span>0.15</span>
Answer:
18q^2 - 52q + 32
Step-by-step explanation:
We can use the Distributive Property to solve this.
(2q-4)(9q-8)
2q(9q) + 2q(-8) + -4(9q) + -4(-8)
18q^2 - 16q - 36q + 32
18q^2 - 52q + 32
18q^2 - 52q + 32
When a number is next to a variable multiply so you problem really is 2(?)=60
