1. C) Both parents contributed a recessive allele
The offspring is homozygous for the recessive allele, which means it has two copies of it. Because each parent contributes one copy of the gene, this means that both parents contributed the recessive allele.
2. D) The offspring can be tall or short
The first cross between TT and tt will yield an F1 generation with the genotype Tt. When this generation is self-pollinated, the cross may result in the following genotypes:
TT, Tt, tt
Which means that the offspring can be tall or short.
Answer:
The bonds that are formed between nitrogenous bases are Hydrogen Bond.
Explanation:
When a hydrogen atom interract with an electronegative atom such oxygen,fluorine hydrogen bond forms,
A single hydrogen bond is weak noncovalent bond but collectively they exerts very strong interraction.
Hydrogen bonding occurs between complementary base pair .For exam An adenine base forms 2 hydrogen bonds with thymine base whereas guanine forms 3 hydrogen bonds with cytosine base.
The hydrogen bonding between complementary is very much important to stabilize the structure of DNA .
Answer:
Increase aldosterone and decrease ADH
Explanation:
Aldosterone causes reabsorption of sodium ions while Antidiuretic hormone (ADH) causes reabsorption of water. Aldosterone also causes water reabsorption due to increased osmotic pressure by reabsorbing sodium ions. But for water reabsorption, Aldosterone has to work along with ADH to increase permeability for water. If we increase Aldosterone and decrease ADH, the sodium ions will be reabsorbed while water cannot be reabsorbed due to decreased permeability of DCT and collecting tubules for water.
Answer:
1/8
Explanation:
Traditional method of solving this problem can be by using the punnett square.
Answer:
The answer to your question is: letter C
Explanation:
From the graph, we can conclude that catalase has a low activity at low temperatures. Activity increases a little at 30°C and this process is the highest at 40°C, after this temperature, activity disminishes again.
Options:
A. This option is wrong because the number of bubbles at this temperatures is low, maybe the enzyme is already denatured.
B. This answer is wrong, at 30°C the enzyme shows a low activity.
C. This answer is correct because at this temperature the enzyme produces the higher amount of bubbles.
D. The activity of the enzyme at 0°C was not tested.
