Need help how to start this and slove it
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Answer:
Step-by-step explanation:
<u>Inequalities</u>
To solve the inequality:
We need to perform the required operations on both sides of the inequality to have the variable w isolated.
First, we subtract 9:
Subtracting 6w:
Operating:
-7w>-1
Now we divide by -7 but recall that when dividing by a negative number, we must flip the inequality sign:
Operating:
Solution:
Hello,
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8