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Umnica [9.8K]
2 years ago
8

I need some help with this question!!! 25 points!!

Mathematics
1 answer:
Aleksandr [31]2 years ago
7 0

Answer:

D. 68 Degrees

Step-by-step explanation:

We have the hypotenuse and the adjacent, so we use cos

Cos-1 of Adjacent / Hypotenuse = 67.9756871

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A triangle has height 4 ft and area 32 ft2. What is the lenght of the base?
Blizzard [7]
A=32ft^2 \\\\ A=\frac{b*h}{2} \\\\ \frac{b*4}{2}=32 \\\\ b=\frac{2*32}{4} \\\\ b=2*8 \\\\ \boxed{b=16ft}
5 0
4 years ago
Read 2 more answers
PLEASE HELP!! I’ll make you the brainlyest!!!
STatiana [176]

Answer:

15

Step-by-step explanation:

Can't really see the graph clearly but the range looks like its from 40-70 so 30 and the amplitude is half of that so 15.

6 0
3 years ago
Read John Muir's "Calypso Borealis" and answer the question. [1] After earning a few dollars working on my brother-in law's farm
skelet666 [1.2K]

Answer:

I think it's the third one

Step-by-step explanation:

Sorry if incorrect

hope this helps!

8 0
3 years ago
(d) Let p represent the probability of a successful long hit. What values of p will make the long hit better than the short hit
seropon [69]

Answer:

The probability of successful  long hit is greater than 0.7083

Step-by-step explanation:

Solution

The expected value for long hit is given below

P (successful hit) * 4.2 + P (Unsuccessful hit) *5.4

so,

= P * 4.2 + (1-p) * 5.4

= 5.4 - 1.2p

Now,

If the expected value of long hit is less than  that of the short it

Then,

5.4 - 1.2p <4.55

P> (5.4 - 4.55)/1.2

P> 0.7083

Therefore the probability of successful  long hit is greater than 0.7083

Note:

Due to my research and findings to this example, the complete question for  is attached below, i solved or Question 2(d) only

8 0
3 years ago
A sphere has a radius of 5 inches. What is its volume?
jarptica [38.1K]

Given  ↓

  • Radius of sphere = 5 in
<h3>To Find ↓</h3>
  • The volume of the sphere
<h3>Calculations ↓</h3>

\blue{\boxed{\mathsf{V=\frac{4}{3} \pi r^3}}

↑ formula for volume of a sphere

r = 5 in

Plug in the value of r and solve :

\blue{\boxed{\mathsf{V=\frac{4}{3}\pi (5)^3}}}

Simplify as follows :

\blue{\boxed{\mathsf{V=\frac{4}{3}\pi *125} }}

\blue{\boxed{V=\frac{4}{3} *392.7}}

Final Step :

\blue{\boxed{\pmb{V=523.6\:in\:^3}}

\footnotesize\text{hope\:helpful}

4 0
2 years ago
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