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Lelu [443]
2 years ago
12

If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2

(x - pi divided by three), what should be used for Xmin and Xmax? Plz explain why because this question is seriously confising me.

Mathematics
1 answer:
erica [24]2 years ago
8 0
Hello,

y=5+3*cos (2(x-π/3))

The function is periodic with periode=2π.


-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8


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Ava’s graph is a vertical translation of f(x) = x^2.

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Given:

Ava graphs the function h(x) = x^2 + 4.

Victor graphs the function g(x) = (x + 4)^2

To find y intercept we plug in 0 for x

h(x) = x^2 + 4

h(x) = 0 + 4= 4

So ,Ava’s graph has a y-intercept of 4.

Ava graphs the function h(x) = x^2 + 4

If any number is added at the end then the graph will be shifted up. 4 is added at the end so there will be vertical translation.

Hence , Ava’s graph is a vertical translation of f(x) = x^2. Also Ava moved 4 units up from f(x) = x^2 in a positive y- direction.

Victor graphs the function g(x) = (x + 4)^2

If any number added with x then the graph will be shifted left. the graph will be shifted in negative x direction.


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Answer:

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Step-by-step explanation:

We can use either angle, but I'm going to use the one on the bottom. So, in order to find x, we need to use tangent. One side we know is the adjacent, and the side we don't know is the opposite, therefore we need tangent. Here's the equation:

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Obviously, we can't have a root in our denominator, so we need to get rid of it somehow. Here's how:

We multiply the denominator of the fraction by \sqrt{2}. \sqrt{2} multiplied by itself is simply 2. Try it! We also want to multiply the numerator by \sqrt{2}, but there isn't really a number we can use with that, so we'll just add it to the side. The equation you have now is:

tan(45)=\frac{x\sqrt{2} }{2}

Let's try to work this out now. Since the denominator is 2, we have to multiply both sides by it to find x.

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