Answer:
410-(30x8) or 3(0xw)
Step-by-step explanation:
We know that
A number written out showing the sum of
each place value in the number is a number in expanded form.
<span> When writing numbers in </span>expanded form<span>, we must remember that it simply means to extend the </span>digits<span>, or numbers, out according to their place value
Examples</span>
![2,583=2,000+500+80+3 \\ 10,320=10,000+300+20 \\ 534.75=500+34+0.7+0.05](https://tex.z-dn.net/?f=2%2C583%3D2%2C000%2B500%2B80%2B3%20%5C%5C%2010%2C320%3D10%2C000%2B300%2B20%20%5C%5C%20534.75%3D500%2B34%2B0.7%2B0.05)
<span>
the answer isPlace Value</span>
30x + 42 = 6(5x + 7) you can understand it now
Answer:
1/6
Step-by-step explanation:
Answer:
Area of second circle = 56cm² +
Area of second circle = 2179.71cm²
Step-by-step explanation:
let the radius of the small circle be r and that of the big circle be R
Area small circle = ![\pi r^{2}](https://tex.z-dn.net/?f=%5Cpi%20r%5E%7B2%7D)
Area Big circle = ![\pi R^{2}](https://tex.z-dn.net/?f=%5Cpi%20R%5E%7B2%7D)
Area Big circle - Area small circle = 56cm²
-
=56cm²
The second circle is the bigger circle.
Area of second circle -
=56cm²
Area of second circle = 56cm² +
r =26cm
Area of second circle = 56cm² +
Area of second circle = 56cm² + ![\pi* 26^{2}](https://tex.z-dn.net/?f=%5Cpi%2A%2026%5E%7B2%7D)
Area of second circle = 56cm² + ![\pi* 26^{2}](https://tex.z-dn.net/?f=%5Cpi%2A%2026%5E%7B2%7D)
Area of second circle = 56cm² + 2123.71
Area of second circle = 2179.71cm²