3 years ago

3(x + y) (2x - 3y) + (x + y)×2 factorize

Mathematics

1 answer:

Vesna [10]3 years ago

3 0

Answer:

(x + y) (6 x - 9 y + 2)

6 x^2 - 3 x y + 2 x - 9 y^2 + 2 y

1\/24 (12 x - 3 y + 2)^2 + 1\/24 (-225 y^2 + 60 y - 4)

Step-by-step explanation:

its one of these 3 answers

You might be interested in

How to write polynomial with given zeros and degree and leading coefficient?

geniusboy [140]

If the zeros are r1,r2, ..., rn and the leading coefficient is a

then
p(x)=a(x-r1)(x-r2)....(x-rn)

8 0

4 years ago

I’m just not getting it! I need step by step.

Alexus [3.1K]

Answer:

$7x + 10 + x + 20 + 2x \\ 7x + x + 2x + 10 + 20 \\ 10 x + 30 \\ x = \frac{30 }{10} \\ x = 3 \\ (7x + 10) = 7 \times 3 + 10 = 31 \\ (x + 20) = 3 + 20 = 23 \\ (2 \times 3) = 6$

Step-by-step explanation:

Please mark as brainliest

8 0

3 years ago

Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give

Aloiza [94]

Answer:

$y = 4e^2x - 3e^2$

Step-by-step explanation:

$f(x) = e^{2x^2}$

lets calculate the derivate of f using the chain rule:

$f'(x) = e^{2x^2}* (2x^2)' = e^{2x^2}*4x = 4e^{2x^2}x$

we have that f'(1) = 4e^2, hence the equation is

$y = f(1) + f'(1) (x-1) = e^2 + 4e^2(x-1)$

or, equivalently,

$y = 4e^2x - 3e^2$

4 0

3 years ago

Describe one exercise you did that helps improve your striking and your reaction time skills (at least one of your exercises mus

Serggg [28]

Answer:

Id sat playing as a goal keeper in football (or soccer )

Step-by-step explanation:

my reaction time and my reflexes are amazing cuz i play alot of soccer nad i thinks that's what helped me, not a exercise but thought this might help

7 0

3 years ago

Read 2 more answers

I will give brainliest and snap to whoever can help me(;´༎ຶٹ༎ຶ`)

koban [17]

Answer:

the answer is b i think. because it says 43 and -2

7 0

3 years ago

3(x + y) (2x - 3y) + (x + y)×2 factorize​

3(x + y) (2x - 3y) + (x + y)×2 factorize