Answer:
The boiling point of NaBr is higher than that of Na2S
Explanation:
Bromine has higher electronegativity as compared to the sulphur. The ionic strength of the bond formed with Sodium is higher in the NaBr compound. The higher the ionic bond strength the higher will be the boiling point
Also the size of bromine is large as compared to that of sulphur. Large molecules consists of more electron and hence they create der Waals attractive forces due to which the boiling point of compound increases.
Hence, the boiling point of NaBr is higher than that of Na2S
<h3>
Answer:</h3>
23 grams Na
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Explanation:</h3>
- Molarity is the concentration of a solution in moles per liter.
- Therefore, a solution with a molarity of 3M contains 3 moles of solute in 1 liter of solution, while a solution with 2M contains 2 moles of solute in 1 liter of solution.
Thus, 3 M = 3 moles/liter
2 M = 2 moles /liter
The difference is 1 mole/Liter
But, 1 mole of sodium 23 g
Therefore;
Mass of sodium = moles × Atomic mass
= 1 mole × 23 g/mol
= 23 g
Therefore a 3 M solution contains 23 g of sodium more than a 2 M solution.
Answer:C. Compounds are the smallest unit of an element that occur on the periodic table!!
Explanation:
