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artcher [175]
3 years ago
11

Is a dibasic acid the same as a strong acid​

Chemistry
2 answers:
Kisachek [45]3 years ago
7 0

Answer:

Since all the acid molecules have split into ions, there will be more H+ ions in a strong acid than a weak acid, hence it's pH is lower! E.g. Hydrochloric acid HCl, nitric acid HNO3. If one mole of an acid is neutralised by 2 moles of NaOH, then the acid is dibasic!

Explanation:

hope it helps

good day

thank u ✌️

gregori [183]3 years ago
7 0

Answer:-

Since all the acid molecules have split into ions, there will be more H+ ions in a strong acid than a weak acid, hence it's pH is lower! E.g. Hydrochloric acid HCl, nitric acid HNO3. If one mole of an acid is neutralised by 2 moles of NaOH, then the acid is dibasic!

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You were instructed to add 1.0 mL out of 4.0 mL of an undiluted sample to 99 mL of sterile diluent. Instead, you add the entire
finlep [7]

Answer:

A.) Intended dilution factor : 0.01

B.) Actual dilution factor: 0.039

Explanation:

Dilution factor(DF) is ratio of the volume of the undiluted sample to total volume of diluted solution

A.) What was your intended dilution factor

This would be the the addition 1.0ml from 4.0ml to 99ml of sterile

Volume of sterile diluent = 99ml

Volume of Undiluted sample = 1.0ml

Total volume of diluted solution = 99ml + 1m = 100ml

Dilution factor = Volume of undiluted sample ÷ Total volume of diluted solution

Dilution factor = 1:100

= 1ml ÷ 100ml

= 0.01

B.) What was your actual dilution factor?

This would be the entire addition of 4.0ml to 99ml sterile diluent

Volume of sterile diluent = 99ml

Volume of Undiluted sample = 4.0ml

Total volume of diluted solution = 99ml + 4.0ml = 103ml

Dilution factor = Volume of undiluted sample ÷ Total volume of diluted solution

Dilution factor

= 4:103

= 4ml ÷ 103ml

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8 0
3 years ago
Para el elemento de Z-56 b, que formula minima tiene el compuesto que forma con 17-cl¿ c, que tipo de union hay en dicho compues
inessss [21]

Answer:

ver explicacion

Explanation:

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El cloruro de bario es un compuesto iónico.

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erastova [34]
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I really need help with this before 5:10
gtnhenbr [62]
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