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Dafna1 [17]
2 years ago
14

20 L of nitrogen gas are collected at a temperature of 50°C and 2 atm. How many grams of nitrogen gas were collected?

Chemistry
1 answer:
Andreas93 [3]2 years ago
8 0

Answer:

0.1077 grams

Explanation:

First we will employ the ideal gas law to determine the number of moles of nitrogen gas.

PV=nRT

P=2 atm

V=20L

R=0.08206*L*atm*mol^-1*K^-1

T=323.15 K

Thus, 2atm*20L=n*0.08206*L*atm*mol^-1*K^-1*323.15K

K, atm, and L cancels out. Thus n=2*20mol/0.08206*323.15=1.5 moles

Lastly, we must convert the number of moles to grams. This can be done by dividing the number of moles by the molar mass of nitrogen gas, which is 14 grams.

1.5/14=0.1077 grams

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In this case, we can see that the number 34,560 has five significant figures, it means that if we want to write it with three, we must take the 3, 4 and 5 only. Nevertheless, since the 6 after the five is greater than 5, we can round such five to 6, so we obtain:

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However, the decimal places cannot get lost, therefore, we move the given thousand  to the three, so the number turns out:

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