Answer:
2nd
Explanation:
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Answer : The rate of the reaction if the concentration of
is doubled is, 0.006 M/s
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The balanced equations will be:

In this reaction,
and
are the reactants.
The rate law expression for the reaction is:
![\text{Rate}=k[CH_3Br][NaOH]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BCH_3Br%5D%5BNaOH%5D)
As we are given that:
= concentration of
= 0.100 M
= concentration of
= 0.100 M
Rate = 0.0030 M/s
Now put all the given values in the above expression, we get:


Now we have to calculate the rate of the reaction if the concentration of
is doubled.
![\text{Rate}=k[CH_3Br][NaOH]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BCH_3Br%5D%5BNaOH%5D)


Thus, the rate of the reaction if the concentration of
is doubled is, 0.006 M/s
Answer:

Explanation:
The compound
is
.
The reaction included are:
(because bromine is less reactive than chlorine)
But , because of hexane the solution get dilute and its color changes to orange.
Now, NaI is added and we know Br is more reactive than I.
Therefore it replace it.
Reaction: 
Purple color develop due to formation of Iodine.
The molecular element describes the amount of protons, neutrons, and electrons found in an atom
An atomic element is the subject in the formula such as ... sulfur, carbon, or oxygen