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djyliett [7]
4 years ago
12

What is equal to one-hundredth of 36? Is it 0.36÷0.12 or 0.30×1.2 or 36÷1.2?

Mathematics
2 answers:
nasty-shy [4]4 years ago
8 0
0.36/0.12 is 3, which is not one-hundredth of 36.
0.3*1.2 is 0.36, which, multiplied by 100, is 36.
36/1.2 is 30, which is not one-hundredth of 36.
The answer is 0.3*1.2.
Vladimir [108]4 years ago
8 0
One-hundredth of 36 is equal to 36 divided by 100.

which equals .36

0.30 x 1.2 = .36
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\begin{aligned} & 2x+7y = 3 \\\\ & x=-4y \end{aligned}
zheka24 [161]

Answer:

x = 12 , y = -3

Step-by-step explanation:

Solve the following system:

{2 x + 7 y = 3 | (equation 1)

x = -4 y | (equation 2)

Express the system in standard form:

{2 x + 7 y = 3 | (equation 1)

x + 4 y = 0 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 7 y = 3 | (equation 1)

0 x+y/2 = -3/2 | (equation 2)

Multiply equation 2 by 2:

{2 x + 7 y = 3 | (equation 1)

0 x+y = -3 | (equation 2)

Subtract 7 × (equation 2) from equation 1:

{2 x+0 y = 24 | (equation 1)

0 x+y = -3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 12 | (equation 1)

0 x+y = -3 | (equation 2)

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3 years ago
What is the next step after using the distributive<br><br> property?
e-lub [12.9K]

Answer:

If it's a simple equation such as 2 (x + y), the next step after applying the distributive property is to do the multiplication and simplify the terms.

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After applying the distributive property, the next step is to separate the variables to one side, like collecting like terms and then solving the now simplified equation.

Step-by-step explanation:

For a normal equation, the distributive property, also called the distributive law of division and multiplication helps to use the variable outside the bracket to multiply the sum of terms in the bracket. For example.

2 (x + y)

The distributive property enables us to say

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So, the next step after applying the distributive property is to simplify the equation.

But in solving an equation such as

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We then operate variables, collect like terms on one side

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3 years ago
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