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Leona [35]
3 years ago
9

An airplane is flying at an altitude of 3,000 ft. The pilot dives 988 feet and then rapidly climbs 748 feet. The pilot then dive

s again 885 feet before making another climb of 1,099 feet. How far above or below an altitude of 3,000 feet is the airplane?
Mathematics
1 answer:
nalin [4]3 years ago
6 0
Start off with initially calculating those numbers to find out how far above or below the airplane is from the altitude of 3000 feet. 

To clear things up, when an aircraft dives, the altitude of how high it is traveling decreases. When an aircraft climbs, the altitude of the aircraft increases. When it mentions that the aircraft starts to dive, you need to subtract. When it climbs, you need to add. 

As the pilot initially dives the plane 988 feet and rapidly climbs 748 feet, you'd need to form an equation which contributes those numbers. It can be illustrated as
3000 - 988 + 748, which is equal to 2760. 
The pilot then dives again 885 feet before making another climb of 1099 feet. Adding on to the previous answer we received, this can be represented as 2760 - 885 + 1099, which equals to 2974. 

You can conclude that the airplane is now travelling at an altitude of 2974 feet. To find out how far above or below the airplane is from an altitude of 3000 feet, simply subtract those numbers. 

3000 - 2974 = 26

The aircraft is travelling <u>26 feet</u> below an altitude of 3000 feet. 
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Umnica [9.8K]

fourty four percent hope this helps !

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3 years ago
Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG
qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

  1. Opposite sides are equal and parallel.
  2. Opposite angles are equal to each other.
  3. Consecutive angles are supplementary
  4. The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

5 0
3 years ago
Give Brainiest
swat32

Answer:

A) rate of change would be dividing the number of songs wanted (150) by the number of weeks downloading (5)

150/5 = 30

 since the total quantity wanted is becoming less every week the rate of change would be negative so it becomes -30

Initial value is 150, which is the total number of songs they want

             B) rate of change would be dividing the number of songs wanted (150) by the number of weeks downloading (5)

150/5 = 30

 since the total quantity wanted is becoming less every week the rate of change would be negative so it becomes -30

Initial value is 150, which is the total number of songs they want

4 0
3 years ago
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A 36 ft tree casts a 9 ft shadow at the same time a building casts a 15 ft shadow. How tall is the building?
mote1985 [20]

Answer: The height of the tree is  27f t

Step-by-step explanation: We can set up a proportion comparing the height of each object to the length of the shadow.

h/s

h/15=18/10

Cross multiply

10.h= 18*15

10h=270

Use the multiplicative Inverse

10 h/ 10 = <em><u>270 /10 =27</u></em>

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vaieri [72.5K]
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.

The other three x-coordinates are greater than 1, then they are out of the unit circle.

The unit circle formula is x^2 +y^2 = 1

Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:

y^2 = 1 - x^2

y = (+/-)√(1-x^2)

Substitute the value of x

y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95


6 0
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