Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2.
H - head
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T) = 0.8
urn
3 red and 5 blue
when heads is obtained
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12
when tails is obtained
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3
using bayes rule the answer can be found out,
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
= 0.12 / (0.12 + 0.3)
= 0.12 / 0.42
= 0.286
the final answer is 0.286
Answer: B
Step-by-step explanation:
you use the coordinates to find the sides
8x.......................
Total number of chips = 4+ 6 = 10
Number of white chips = 4
Probability of picking a white chip =

This white chip is not replaced back into the bag. This will reduce the number of white chips in the bag by 1 and reduce the total number of chips in the bag by 1.
So, now the total number of chips in the bag = 3 + 6 = 9
Number of white chips in the bag = 3
Probability of picking a white chip =

Thus, the probability of picking two white chips will be =
Therefore, option B gives the correct answer.