Answer:
<h2><em><u>Pythagorean </u></em><em><u>theorem </u></em><em><u>reads </u></em><em><u>as:</u></em></h2>
<h2><em><u>H²</u></em><em><u>=</u></em><em><u>P²</u></em><em><u>+</u></em><em><u>B</u></em><em><u>²</u></em></h2>
<h2><em><u>in </u></em><em><u>which </u></em><em><u>p </u></em><em><u>reads </u></em><em><u>as </u></em><em><u>perpendicular </u></em><em><u>so </u></em></h2>
<h2><em><u>P²</u></em><em><u>=</u></em><em><u>H²</u></em><em><u>-</u></em><em><u>B²</u></em></h2>
<em><u>
</u></em>
Step-by-step explanation:
I am not sure what your problem here is.
you understand the inequality signs ?
anyway, to get
6×f(-2) + 3×g(1)
we can calculate every part of the expression separately, and then combine all the results into one final result.
f(-2)
we look at the definition.
into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?
is -2 < -2 ? no.
is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.
so, we have to use
1/3 x³
for x = -2 that is
1/3 × (-2)³ = 1/3 × -8 = -8/3
g(1)
again, we look at the definition.
into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?
is 1 > 2 ? no.
is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.
so we have to use
2×|x - 1| + 3
for x = 1 we get
2×0 + 3 = 3
6×f(-2) = 6 × -8/3 = 2× -8 = -16
3×g(1) = 3× 3 = 9
and so in total we get
6×f(-2) + 3×g(1) = -16 + 9 = -7
Answer:
an integer is a rational number sometimes(eg.17=17/1) but not always.
a rational number can be written in the form p/q where p and q are integers.
Step-by-step explanation:
Answer:
88 Tickets were sold
Step-by-step explanation:
20*$4=$80
$216-$80=$136
$136/2=68
20+68=88 tickets
Answer:
<em>Answer: C. 32 cm</em>
Step-by-step explanation:
<u>Triangle Inequality Theorem
</u>
Let y and z be two of the side lengths of a triangle. The length of the third side x cannot be any number. It must satisfy all the following restrictions:
x + y > z
x + z > y
y + z > x
Combining the above inequalities, and provided y>z, the third size must satisfy:
y - z < x < y + z
We know the triangle has two congruent angles, which means the triangle is isosceles, i.e., it has two congruent sides.
We are given two side lengths of 16 cm and 32 cm. The third side must have a length of 16 cm or 32 cm for the triangle to be isosceles.
If the third side had a length of 16 cm then the lengths would be 16-16-32. But that combination cannot form a triangle because of the condition stated above.
If y=16, z=16, and x=32 (the worst possible combination), then the inequality
0 < x < 32
wouldn't be satisfied, thus the third side cannot have a length of 16 cm and it must have a length of 32 cm
Answer: C. 32 cm
