(d): y = mx+n
m = -2/3 ⇒ y = (-2/3)x +n
A(-4, 6) ∈ d ⇒ 6 = (-2/3)·(-4) +n ⇒ 6 = 8/3 +n ⇒
⇒ n = 6 - 8/3 ⇒ n = 10/3
Now, we have:
y = (-2/3)x +10/3
Answer:
The big polygon is double the size of the original, So the side question mark is 5 and the degrees is 1, 26.5 and 2, 41 degrees
Step-by-step explanation:
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
Answer:
the ordered pair is (2,-1)
Step-by-step explanation:
We need to solve the system of equations using elimination method
12x - y = 25 eq(1)
9x + y = 17 eq(2)
Adding eq(1) and eq(2)
12x - y = 25
9x + y = 17
___________
21x = 42
x = 42/21
x= 2
Now, putting value of x in equation 1
12x - y = 25
12(2) -y = 25
24 -y = 25
Adding -24 on both sides
24 -y-24 = 25-24
-y = 25-24
-y = 1
Multiply both sides by -1
y = -1
the value of x = 2 and y = -1
So, the ordered pair is (2,-1)