Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5. 1) Write an equation for li
1 answer:
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Write the function as
f(x) = x² + 6x - 4
Note that
x² + 6x = (x + 3)² - 9
Therefore
f(x) = (x 3)² - 9 - 4
= (x + 3)² - 13
The vertex is at (-3, -13)., and the curve opens upward.
The axis of symmetry is x = -3.
Answer:
The vertex of the function is (-3, 13).
The graph increases over the interval (-3, -∞)
f(x) = x² + 6x - 4
Note that
x² + 6x = (x + 3)² - 9
Therefore
f(x) = (x 3)² - 9 - 4
= (x + 3)² - 13
The vertex is at (-3, -13)., and the curve opens upward.
The axis of symmetry is x = -3.
Answer:
The vertex of the function is (-3, 13).
The graph increases over the interval (-3, -∞)
Okay so this is how i did it but idk if it’s right.
so i multiples the top and bottom by square root of 3 to get rid of the square root of 3
then i was left with 8-1/2(1) and got 7/2
so i multiples the top and bottom by square root of 3 to get rid of the square root of 3
then i was left with 8-1/2(1) and got 7/2