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aalyn [17]
3 years ago
15

Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5. 1) Write an equation for li

ne p
Mathematics
1 answer:
wel3 years ago
4 0

Answer:

y = -\frac{1}{3}x -3

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point slope form.

y = 3x + 5 is q. It has a slope of 3. So p will have a slope of -1/3.

y - y_1 = m(x-x_1)\\y - -5 = -\frac{1}{3}(x - 6)\\y + 5 = -\frac{1}{3}x + 2\\y = -\frac{1}{3}x -3

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4 0
3 years ago
If a woodchuck could chuck 2<br> pieces of wood every hour, how big is a beavers dam?
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Answer:

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3 years ago
Expand and simplify 5(3x+2)-2(4x-1)
blsea [12.9K]

5(3x+2)-2(4x-1)

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6 0
2 years ago
Find the slope of the line passing through the points (-5, 3) and (7,9).
dybincka [34]

Answer:

\huge\boxed{slope=\dfrac{1}{2}=0.5}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points

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Substitute:

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5 0
3 years ago
Read 2 more answers
For the following figure what’s the value of x?
Leto [7]

Answer:

x = 8 in

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x = 8

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Because opposite angles are equal.

8² + 8² = hyp²

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hyp = 8sqrt(2)

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8 0
3 years ago
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