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aalyn [17]
3 years ago
15

Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5. 1) Write an equation for li

ne p
Mathematics
1 answer:
wel3 years ago
4 0

Answer:

y = -\frac{1}{3}x -3

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point slope form.

y = 3x + 5 is q. It has a slope of 3. So p will have a slope of -1/3.

y - y_1 = m(x-x_1)\\y - -5 = -\frac{1}{3}(x - 6)\\y + 5 = -\frac{1}{3}x + 2\\y = -\frac{1}{3}x -3

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Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0, 2).
arsen [322]

Answer:

y=-2x+2

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope</u>

m=\frac{y_2-y_1}{x_2-x_1} where the two given points are (x_1,y_1) and (x_2,y_2)

Plug in the given points (-1, 4) and (0, 2)

=\frac{2-4}{0-(-1)}\\=\frac{-2}{0+1}\\=\frac{-2}{1}\\= -2

Therefore, the slope of the line is -2. Plug this into y=mx+b:

y=-2x+b

<u>2) Determine the y-intercept</u>

y=-2x+b

Recall that the y-intercept is the value of y when the line crosses the y-axis, meaning that the y-intercept occurs when x is equal to 0.

One of the given points is (0,2). Notice how y=2 when x=0. Therefore, the y-intercept of the line is 2.

Plug this back into the equation:

y=-2x+2

I hope this helps!

6 0
3 years ago
LAST ATTEMPT MARKING AS BRAINLIEST!! (Graph the image of the figure using the dilation given)
Iteru [2.4K]
L’ (4.5,0) J’(-4.5, -4.5) K’(-4.5,4.5) i think
5 0
2 years ago
Read 2 more answers
I really need help please help me
alexira [117]

Answer:

top right

Step-by-step explanation:

If you imagine yourself building with that model you can see its that one

8 0
3 years ago
What is the equation of a line that passes through the points (1,6) and (2,1)?
algol13

Answer:

y = -5x+11

Step-by-step explanation:

3 0
3 years ago
Suppose that a cyclist began a 374 mi ride across a state at the western edge of the​ state, at the same time that a car traveli
kherson [118]
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph

4 0
3 years ago
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