Question

Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5. 1) Write an equation for line p

Answer 1

Answer:

$y = -\frac{1}{3}x -3$

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point slope form.

y = 3x + 5 is q. It has a slope of 3. So p will have a slope of -1/3.

$y - y_1 = m(x-x_1)\\y - -5 = -\frac{1}{3}(x - 6)\\y + 5 = -\frac{1}{3}x + 2\\y = -\frac{1}{3}x -3$