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aleksklad [387]
4 years ago
13

Help me on this math question thank you

Mathematics
1 answer:
Vitek1552 [10]4 years ago
4 0

Answer:

  • C for question 1
  • A for question 2

Step-by-step explanation:

First Question

What you need to do here is pick an answer that will result in a decrease. If you have something like 1.3 * e ^ (0.038 * t), what will happen when t = 20

P = 1.3 * e^(0.038*20) = 1.3*e^0.76 = 2.77 which is getting bigger not smaller.

So what you want is something like 1.3 * e^-0.76 = 0.67

So which question is configured that way?

It's either C or D. but which one? It cannot be D. 0.38 is far too big: it does not represent 3.8%

C does represent 3.8% as a decimal. It is the correct answer.

Answer: C

Second Question

Every time she sells a ticket, the total that she gets is 4 more than what she had before.

The variation is a direct one. It is y = k*x. But what is k? Is it 4 or is it 1/4?

Read the first sentence above. She gets 4 dollars more, not 1/4 of a dollar.

C and D are both wrong because those equations think she is getting 1/4 more.

B is wrong because it says that the relationship is inverse. It is not. It is direct.

The answer is A


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At the laundromat, Carol used to pay $1.50 per load, but the company has increased the price per load by 20%. Estimate the amoun
RideAnS [48]

Answer:

$10.80 (about $11)

<em>Brainliest, please!</em>

Step-by-step explanation:

20% = 0.2

+20% = x 1.2

1.5 x 1.2 = 1.8

1.8 x 6 = 10.8

7 0
3 years ago
state the domain and range of the given relation and then determine if it is a function -1,3 0,3 1,3 2,3 3,3​
cupoosta [38]

Answer:

D{-1, 0, 1, 2, 3}       R{3}

Step-by-step explanation:

It is a function. Although the range is all the same number, it still qualifies as a function

7 0
3 years ago
Read 2 more answers
Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3
VashaNatasha [74]
  The correct answer is:  Answer choice:  [A]:
__________________________________________________________
→  "\frac{u}{u-3} " ;  " { u \neq ± 3 } " ; 

          →  or, write as:  " u / (u − 3) " ;  {" u ≠ 3 "}  AND:  {" u ≠ -3 "} ; 
__________________________________________________________
Explanation:
__________________________________________________________
 We are asked to simplify:
  
  \frac{(u^2+3u)}{(u^2-9)} ;  


Note that the "numerator" —which is:  "(u² + 3u)" — can be factored into:
                                                      →  " u(u + 3) " ;

And that the "denominator" —which is:  "(u² − 9)" — can be factored into:
                                                      →   "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→    \frac{u(u+3)}{(u-3)(u+3)}  ;

___________________________________________________________

→  We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" \frac{(u+3)}{(u+3)} = 1 "  ;

→  And we have:
_________________________________________________________

→  " \frac{u}{u-3} " ;   that is:  " u / (u − 3) " ;  { u\neq 3 } .
                                                                                and:  { u\neq-3 } .

→ which is:  "Answer choice:  [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ; 

and if the denominator is "(u − 3)" ;  the denominator equals "0" when "u = -3" ;  as such:

"u\neq3" ; 

→ Note:  To solve:  "u + 3 = 0" ; 

 Subtract "3" from each side of the equation; 

                       →  " u + 3 − 3 = 0 − 3 " ; 

                       → u =  -3 (when the "denominator" equals "0") ; 
 
                       → As such:  " u \neq -3 " ; 

Furthermore, consider the initial (unsimplified) given expression:

→  \frac{(u^2+3u)}{(u^2-9)} ;  

Note:  The denominator is:  "(u²  − 9)" . 

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ; 

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________ 

→  " u² − 9 = 0 " ; 

 →  Add "9" to each side of the equation ; 

 →  u² − 9 + 9 = 0 + 9 ; 

 →  u² = 9 ; 

Take the square root of each side of the equation; 
 to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ; 

→ √(u²) = √9 ; 

→ | u | = 3 ; 

→  " u = 3" ; AND;  "u = -3 " ; 

We already have:  "u = -3" (a value at which the "denominator equals "0") ; 

We now have "u = 3" ; as a value at which the "denominator equals "0"); 

→ As such: " u\neq 3" ; "u \neq -3 " ;  

or, write as:  " { u \neq ± 3 } " .

_________________________________________________________
6 0
3 years ago
Find the value of 4y+1 given that -11y-9=2 .
adoni [48]
-11y-9=2
-11y=11
y=-1

4[-1]+1
-4+1=-3

-3 is your answer.
6 0
3 years ago
Can someone please help me outt
saveliy_v [14]

Answer:

ASA

Step-by-step explanation:

We can see that the triangle has at least one similar side and one similar angle. We can also see that the triangles meet at a point, so they must have the same angle at that point where they connect. So that leads us to our answer being ASA since they have two similar angles and one similar side. This is the answer that I think is correct just by looking at the image. I haven't take this class since last year, so this is simply from memory. Correct me if I am wrong!

6 0
3 years ago
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